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#2 (permalink) Fri Aug 17, 2007 20:11 pm Tough GRE Math Questions |
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| Please answer the questions. I am in need of help very much. |
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Yoazzole New Member
Joined: 17 Aug 2007 Posts: 2
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#3 (permalink) Mon Aug 20, 2007 23:27 pm Tough GRE Math Questions |
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#1, A= 32/44 times 12/43, compare then. (sorry i am too lazy to do the calculation) reason:there 32 short at the beginning chosen from totally 44pens, then choose a long one from the remaining 43 (44-1). is this clear?
#2, i agree with you, as a mathematics student, the answer to this question is : no anwser in real number,(but ok is complex number). anyway, i would choose "not determined" for this one. yeah, i hate the gre quan test, because i have seen a lot of them are stupid with mathematical mistake or unprecise statement.
#3, sorry, i really don't understand the question "if at least one topping has to be used" to be use for what? "each topping cannot be used more than once" more than once in what? in each sanwich? and for the toppings, do you consider the up or down side? in my view, up and down is the same thing. this is a good example for what i said, "GRE quan test is stupid and not precise" if i have to choose, i would say B is greater.
again, i wish you have good luck that without seeing the unprecise question. even as a math major, i am not confident to get a perfect score, if these type of unprecise questions show up. |
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Kevinlee001 New Member
Joined: 20 Aug 2007 Posts: 5 Location: Chicago
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#4 (permalink) Sat Aug 25, 2007 20:23 pm Tough GRE Math Questions |
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1. 32/44 * 12/43 = 8/11 * 12/43 = 96/473 = 20% (approx) 2. Indeterminate. The problem is not solved in real space. 3. 15 is correct: Let's say the four toppings are a, b, c and d. a: You can make two classes of sandwiches- with and without 'a' b: 2- with or without 'b' c: 2 d: 2
There are 16 combinations (2*2*2*2). Since a sandwich must contain at least one topping (else it is just bread slices), the combination with none of the toppings should not be considered. So 15 sandwiches. |
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WarriorOfDiscord New Member
Joined: 25 Aug 2007 Posts: 1 Location: India
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#5 (permalink) Wed Sep 19, 2007 4:24 am Tough GRE Math Questions |
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@question 3:
I am sure A is supposed to be 33, since this is closest to B value (easier to miscalculate) and 33 results from 4! + 3! + 2! + 1!. This would be the case if you take the arrangement of the "toppings" into account. But I don't exactly know what a sandwich topping is so maybe I'm writing bullshit :D
I have to say it's lame that one has to complete the missing information in the questions by mindreading the test-writers - but then it's easy to mindread them, they are just like the bad guys in the movies: not very smart, evil and they want you to fail :( |
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Immortal I'm new here and I like it ;-)
Joined: 17 Sep 2007 Posts: 14
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#6 (permalink) Wed Sep 19, 2007 18:30 pm Tough GRE Math Questions |
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2x + 4y = 16 3x + 6y = 30
multiplying equations by 2 and 3 respectively we get
6x+12y=48 6x+12y=60 ----------------
well the equation given here is wrong you cannot have same values of x and y giving different answers on right hand side. |
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Neeshu I'm new here and I like it ;-)

Joined: 19 Sep 2006 Posts: 28
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#7 (permalink) Tue Oct 09, 2007 2:18 am Tough GRE Math Questions |
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hello friends, i am bhanupratap,studied m.res in life sciences at glasgow university,.recently started gre preparation,.any one could suggest me some good material for quants. i appreciate you all,all the best thanks |
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Bhanupratap New Member
Joined: 09 Oct 2007 Posts: 7 Location: Glasgow
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#8 (permalink) Wed Oct 07, 2009 5:26 am Tough GRE Math Questions |
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A vegetarian sandwich shop has a choice of 4 different sandwich toppings. The number of different types of sandwiches that can be made if at least one topping has to be used and each topping cannot be used more than once.
Answer:
If at least one topping has to be used means you will have sandwiches with 1,2,3,4 topping? Right,
So the total numbers of different types of sandwiches that can be made is =(S 1 topping + S 2 topping + S 3 topping + S 4 topping)
S=sandwiches
S 1 topping= 4 (since we have 4 toppings) and so on,
If you cant see that use the combination formula.
S 1 topping=4! / (4-1)! 1! =4
S 2 topping=4! / (4-2)! 2! =6 S 3 topping=4! / (4-3)! 3! =4
S 4 topping=4! / (4-4)! 4! =1 (remember 0! =1)
Total different sandwiches are 4+6+4+1=15.
Hope it helps,, |
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Pivarela New Member
Joined: 07 Oct 2009 Posts: 1
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#9 (permalink) Fri Jan 08, 2010 12:12 pm Tough GRE Math Questions |
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The problem with the third problem is that the sandwich with, let's say, lattice on onion and the the sandwich with onion on lattice are different sanwiches. So, to calculate the total number of sandwiches, we should use arrangements, not combinations. number of arrangement of m items out of n ones is A(n,m)=n!/(m-n)! A(4,1)=4 A(4,2)=12 A(4,3)=24 A(4,4)=24 Total 24+24+12+4=64>32. |
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GeneralVimes I'm new here and I like it ;-)

Joined: 08 Jan 2010 Posts: 13
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#10 (permalink) Thu Feb 11, 2010 2:27 am Tough GRE Math Questions |
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I have two questions please solve them:-
1. Two researchers spent a total of 35 hours on a certain project. One of the researchers spent 25 percent fewer hours on the project than the other.
Column A:
The difference between the number of house spent by each
Column B:
7
Column B is the answer
2. A rectangular rug covers half of a rectangular floor that is 9 feet wide and 12 feet long. If the dimensions of the rug are in the same ratio as those of the floor, how many feet long is the rug?
Answer: 6√2 |
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Waqas.Asim New Member
Joined: 11 Feb 2010 Posts: 4
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#11 (permalink) Sun Feb 14, 2010 16:28 pm Tough GRE Math Questions |
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1. Two researchers spent a total of 35 hours on a certain project. One of the researchers spent 25 percent fewer hours on the project than the other.
It means, that if we take the second researcehr's time as 100%, the first one's time will be 75%. Therefore, the ratio if 75:100=3:4. So, we should divide 35 into the ration of 3:4. We'll get 15 and 20, their difference is 20-15=5<7
2. In order to solve this, we shold know about similarity of geomtry figures. If the dimensions of the rug are in the same ratio as those of the floor, they are called similar rectangles. And the areas of similar figures are in the same ratio as the squares of their linear measures. => The linear measures of similar figures are in the same ratio as the square roots of theis areas.
Here we have, that the area of the rug is twice smaller, that the floor, then, its length will be √2 times smaller, than the length of the floor. This gives us 12/√2=6√2 |
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GeneralVimes I'm new here and I like it ;-)

Joined: 08 Jan 2010 Posts: 13
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#12 (permalink) Sun Feb 14, 2010 19:59 pm Tough GRE Math Questions |
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| Thanks for answering these questions. Your solutions are very helpful. |
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Waqas.Asim New Member
Joined: 11 Feb 2010 Posts: 4
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#13 (permalink) Sun Feb 14, 2010 21:38 pm Tough GRE Math Questions |
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| Welcome :) |
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GeneralVimes I'm new here and I like it ;-)

Joined: 08 Jan 2010 Posts: 13
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#14 (permalink) Fri Jun 04, 2010 6:35 am Tough GRE Math Questions |
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Please activate Javascript in your browser to listen to this audio recording | 66 Listened |
I want to speak with people . If I will speak I can learn more and more language because this is important too much speak and improve language but I don't use this language and I can't speak very well. |
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Lidiya You can meet me at english-test.net

Joined: 29 Mar 2009 Posts: 54 Location: United States
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#15 (permalink) Fri Jun 04, 2010 6:44 am Tough GRE Math Questions |
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Please activate Javascript in your browser to listen to this audio recording | 43 Listened |
Why do you want to leave her here? I DON'T WANT TO tyler BARNETT RUBBED HIS FACE, THEN LET HIS HANDS FALL TO HIS LAP. She is onlly six years old. I dn't want to leave her anywhere, but I don't know what else to do. I can't get the kind of help she needs at home. |
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Lidiya You can meet me at english-test.net

Joined: 29 Mar 2009 Posts: 54 Location: United States
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